mktime

(PHP 4, PHP 5, PHP 7, PHP 8)

mktime — Bir tarih için Unix zaman damgasını döndürür

Açıklama

Verilen değiştirge düzenine göre Unix zaman damgasını döndürür. Bu zaman damgası, Unix Zaman Başlangıcı (1 Ocak 1970 00:00:00 GMT) ile belirtilen zaman arasında geçen süreyi uzun tamsayı türünde saniye olarak belirtir.

Değiştirgeler sağdan sola sıralıdır; böylece belirtilmeyen bir değiştirge yerine yerel tarih ve zamana göre geçerli değerin kullanılması sağlanmıştır.

Notlar

mktime() işlevinin değiştirgesiz çağrılmasının kullanımı önerilmemektedir. Geçerli zaman damgasını almak için time() kullanılabilir.

Değiştirgeler

saat: ay, gün ve yıl'a göre saptanan günün başlangıcına göreli saat sayısı. Negatif değerler günün geceyarısından önceki saatine karşılıktır. 23'ten büyük değerler ertesi günün uygun saatine karşılıktır.
dakika: saat'in başlangıcına göreli dakika sayısı. Negatif değerler önceki saatin dakikalarına, 59'dan büyük değerler ise sonraki saatin dakikalarına karşılıktır.
saniye: dakika'nın başlangıcına göreli saniye sayısı. Negatif değerler önceki dakikanın saniyelerine, 59'dan büyük değerler ise sonraki dakikanın saniyelerine karşılıktır.
ay: Önceki yıl sonuna göreli ay sayısı. 1-12 arasındaki değerler ilgili yılın normal takvim aylarına karşılıktır. 1'den küçük (negatifler dahil) değerler ters sırada önceki yılın aylarına karşılıktır, yani 0 Aralık, -1 Kasım, vb.
gün: Önceki ayın sonuna göreli gün sayısı. 1'den 28, 29, 30 veya 31'e kadar (aya bağlı olarak) değerler ilgili ayın normal günlerine karşılıktır. 1'dek küçükler (negatifler dahil) önceki ayın günlerine karşılıktır, yani 0 önceki ayın son günü, -1 daha önceki günü vb. İlgili ayın gün sayısından büyük değerler sonraki ayın günlerine karşılıktır.
yıl: Yıl sayısı, iki ya da dört hane olabilir. 0-69 değerleri arasında olanlar 2000-2069 ile ve 70-100 arasındaki değerler ise 1970-2000 yıllarıyla eşleşir. Sistemlerdeki time_t türü 32 bit işaretli tamsayı türüyle belirtilmiştir ve günümüzde çok kullanılmaktadır. yıl değiştirgesi için geçerli aralık 1901 ve 2038 arasındadır.

Dönen Değerler

mktime() işlevi verilen değiştirgelerden elde edilen Unix zaman damgası döndürür. Eğer değiştirgeler geçersiz ise işlev false değeriyle döner.

Hatalar/İstisnalar

Bir tarih/zaman işlevine yapılan her çağrı eğer zaman dilimi ayarı geçerli değilse bir E_NOTICE üretir. Ve/veya eğer sistem ayarları veya TZ ortam değişkeni kullanılıyorsa bir E_STRICT veya bir E_WARNING iletisi üretir. Ayrıca bakınız: date_default_timezone_set()

Sürüm Bilgisi

Sürüm:	Açıklama
8.0.0	`saat` artık seçimlik değil.
8.0.0	`dakika`, `saniye`, `ay`, `gün` ve `yıl` artık boş olabiliyor.

Örnekler

Örnek 1 - Basit bir mktime() örneği


<?php
// Öntanımlı zaman dilimini belirtelim.
date_default_timezone_set('UTC');

echo "July 1, 2000 is on a " . date("l", mktime(0, 0, 0, 7, 1, 2000));
// Çıktısı: July 1, 2000 is on a Saturday

echo date('c', mktime(1, 2, 3, 4, 5, 2006));
// Şöyle bir şey basar: 2006-04-05T01:02:03+00:00
?>

Örnek 2 - mktime() örneği

mktime() işlevi tarih hesaplamaları ve geçerlilik denetimi için kullanışlıdır. Aralık dışına çıkan değerleri (ayın 32'si gibi) otomatik olarak doğru hesaplar. Örneğin, aşağıdaki satırların üreteceği dizge "Jan-01-1998" olacaktır.


<?php
echo date("M-d-Y", mktime(0, 0, 0, 12, 32, 1997));
echo date("M-d-Y", mktime(0, 0, 0, 13, 1, 1997));
echo date("M-d-Y", mktime(0, 0, 0, 1, 1, 1998));
echo date("M-d-Y", mktime(0, 0, 0, 1, 1, 98));
?>

Örnek 3 - Ayın son günü

Verilen herhangi bir ayın son günü, gelecek ayın -1'inci değil 0'ıncı günü olarak ifade edilebilir. Aşağıdaki iki örnek de "2000 Şubat'ının son günü: 29" dizgesi üretilecektir.


<?php
$songün = mktime(0, 0, 0, 3, 0, 2000);
echo strftime("2000 Şubat'ının son günü: %d", $songün);
$songün = mktime(0, 0, 0, 4, -31, 2000);
echo strftime("2000 Şubat'ının son günü: %d", $songün);
?>

Ayrıca Bakınız

checkdate() - Miladi tarihi doğrular
gmmktime() - Bir GMT tarihi için Unix zaman damgasını döndürür
date() - Yerel tarihi/saati biçimlendirir
time() - Geçerli Unix zaman damgasını döndürür

add a note

User Contributed Notes 27 notes

down

Alan ¶

15 years ago


Do remember that, counter-intuitively enough, the arguments for month and day are inversed (or middle-endian). A common mistake for Europeans seems to be to feed the date arguments in the expected order (big endian or little endian).

It's clear to see where this weird order comes from (even with the date being big endian the order for all arguments would still be mixed - it's obviously based on the American date format with the time "prefixed" to allow an easier shorthand) and why this wasn't changed (passing the values in the wrong order produces a valid, though unexpected, result in most cases), but it continues to be a source of confusion for me whenever I come back to PHP from other languages or libraries.

down

joseph dot andrew dot hughes at gmail dot com ¶

16 years ago


Just a small thing to think about if you are only trying to pull the month out using mktime and date.  Make sure you place a 1 into day field.  Otherwise you will get incorrect dates when a month is followed by a month with less days when the day of the current month is higher then the max day of the month you are trying to find.. (Such as today being Jan 30th and trying to find the month Feb.)

down

phper ¶

8 years ago


Please mind function is timezone dependent. Timezone independent funciton is gmmktime

down

Rad ¶

10 years ago


Be careful passing zeros into mktime, in most cases a zero will count as the previous unit of time. The documentation explains this yet most of the comments here still use zeroes.

For example, if you pass the year 2013 into mktime, with zeroes for everything else, the outcome is probably not what you are looking for.

<?php
echo date('F jS, Y g:i:s a', mktime(0, 0, 0, 0, 0, 2013)); 
// November 30th, 2012 12:00:00 am
?>

Instead of using 0's, try 1's. This makes more sense (except for minutes/seconds). Maybe not as obvious of a purpose as zeroes to other programmers, though.

<?php
echo date('F jS, Y g:i:s a', mktime(1, 1, 1, 1, 1, 2013));
// January 1st, 2013 1:01:01 am
?>

down

developers at zeros dot co dot id ¶

6 years ago


Please note, mktime requires an integer value, if you use date("H"), date("i"), date("s") as a value, which is actually have a leading zero, you may get "A non well formed numeric value encountered" notice. so you need some tricks like this

mktime( date("G"), intval(date("i")), intval(date("s"), date("n"), date("j"), date("Y") )

Since there are no minute & second without leading zero in the date function, we can use the intval() function or you can cast value type like this to force the value type.

(int) date("i")

down

MarkAgius at markagius dot co dot uk ¶

6 years ago


The following function moves all the parameters in order of most significant (biggest) to least significant (smallest) order.
Year is bigger than month. Month is bigger than day. Day bigger than hours...

Much less confusing than mktime order.

<?php
function mkTimestamp($year,$month,$day, $hours=0,$minutes=0,$seconds=0){
  // Same as mktime() but parameters are in most significant to least significant order.
  return mktime($hours,$minutes,$seconds, $month,$day,$year);
}
?>

down

tom at chegg dot com ¶

13 years ago


I was using the following to get a list of month names.

for ($i=1; $i<13; $i++) {
  echo date('F', mktime(0,0,0,$i) . ",";
}

Normally this outputs -
January,February,March,April,May,June,July,August,
September,October,November,December

However if today's date is the 31st you get instead:
January,March,March,May,May,July,July,August,October,
October,December,December

Why? Because Feb,Apr,June,Sept, and Nov don't have 31 days!

The fix, add the 5th parameter, don't let the day of month default to today's date:

  echo date('F', mktime(0,0,0,$i,1) . ",";

down

thomas_corthals at hotmail dot com ¶

15 years ago


It seems mktime() doesn't return negative timestamps on Linux systems with a version of glibc <= 2.3.3.

down

mh240873 at web dot de ¶

9 years ago


Pay attention that not all days have the same number of seconds (86400s) if you are using date_default_timezone_set(..) and the used timezone has Daylight Saving Time (DST) e.g. "Europe/Berlin". Under PHP 5.5.16 I get the following results:

  $shortday  = mktime(23,59,59, '3','29','2015') - mktime(0,0,0, '3','29','2015) + 1; // result: 82800s  (86400s - 3600s)
  $normalDay = mktime(23,59,59, '1', '2','2015') - mktime(0,0,0, '1', '1','2015) + 1; // result: 86400s  
  $longDay   = mktime(23,59,59,'10','25','2015') - mktime(0,0,0,'10','25','2015) + 1; // result: 90000s  (86400s + 3600s)

Pitfall is noticeable if you are running an iterative loop with a code like:
   echo date( 'd.m.Y', $day );
   $day = $day + 86400;   // 86400 = 24*3600 - frequently used in PHP code

which results in wrong date if $day reaches 2015-10-25 (end of summer time in Germany):
    24.10.2015
    25.10.2015   
    25.10.2015   // Ups! Same date twice in calendar
    27.10.2015

You may workaround this by using date_default_timezone_set('UTC') where all days have the same number of seconds.

down

ronnie dot kurniawan at gmail dot com ¶

15 years ago


Add (and subtract) unixtime:



<?php

function utime_add($unixtime, $hr=0, $min=0, $sec=0, $mon=0, $day=0, $yr=0) {

  $dt = localtime($unixtime, true);

  $unixnewtime = mktime(

      $dt['tm_hour']+$hr, $dt['tm_min']+$min, $dt['tm_sec']+$sec,

      $dt['tm_mon']+1+$mon, $dt['tm_mday']+$day, $dt['tm_year']+1900+$yr);

  return $unixnewtime;

}

?>

down

info at microweb dot lt ¶

13 years ago


Function to generate array of dates between two dates (date range array)



<?php

function dates_range($date1, $date2)

{

   if ($date1<$date2)

   {

       $dates_range[]=$date1;

       $date1=strtotime($date1);

       $date2=strtotime($date2);

       while ($date1!=$date2)

       {

           $date1=mktime(0, 0, 0, date("m", $date1), date("d", $date1)+1, date("Y", $date1));

           $dates_range[]=date('Y-m-d', $date1);

       }

   }

   return $dates_range;

}



echo '<pre>';

print_r(dates_range('2009-12-25', '2010-01-05'));

echo '</pre>';

?>



[EDIT BY danbrown AT php DOT net: Contains a bugfix submitted by (carlosbuz2 AT gmail DOT com) on 04-MAR-2011, with the following note: The first date in array is incorrect.]

down

PHPcoder at freemail dot ig3 dot net ¶

16 years ago


The maximum possible date accepted by mktime() and gmmktime() is dependent on the current location time zone.

For example, the 32-bit timestamp overflow occurs at 2038-01-19T03:14:08+0000Z.  But if you're in a UTC -0500 time zone (such as EST in North America), the maximum accepted time before overflow (for older PHP versions on Windows) is 2038-01-18T22:14:07-0500Z, regardless of whether you're passing it to mktime() or gmmktime().

down

-1

rga at merchantpal dot com ¶

17 years ago


You cannot simply subtract or add month VARs using mktime to obtain previous or next months as suggested in previous user comments (at least not with a DD > 28 anyway).

If the date is 03-31-2007, the following yeilds March as a previous month. Not what you wanted.

<?php
$dateMinusOneMonth = mktime(0, 0, 0, (3-1), 31,  2007 );
$lastmonth = date("n | F", $dateMinusOneMonth);
echo $lastmonth;    //---> 3 | March
?>

mktime correctly gives you back the 3rd of March if you subtract 1 month from March 31 (there are only 28 days in Feb 07).

If you are just looking to do month and year arithmetic using mktime, you can use general days like 1 or 28 to do stuff like this:

<?php
$d_daysinmonth = date('t', mktime(0,0,0,$myMonth,1,$myYear));     // how many days in month
$d_year = date('Y', mktime(0,0,0,$myMonth,1,$myYear));        // year
$d_isleapyear = date('L', mktime(0,0,0,$myMonth,1,$myYear));    // is YYYY a leapyear?

$d_firstdow = date('w', mktime(0,0,0,$myMonth,'1',$myYear));     // FIRST falls on what day of week (0-6)
$d_firstname = date('l', mktime(0,0,0,$myMonth,'1',$myYear));     // FIRST falls on what day of week Full Name

$d_month = date('n', mktime(0,0,0,$myMonth,28,$myYear));         // month of year (1-12)
$d_monthname = date('F', mktime(0,0,0,$myMonth,28,$myYear));         // Month Long name (July)
$d_month_previous = date('n', mktime(0,0,0,($myMonth-1),28,$myYear));         // PREVIOUS month of year (1-12)
$d_monthname_previous = date('F', mktime(0,0,0,($myMonth-1),28,$myYear));     // PREVIOUS Month Long name (July)
$d_month_next = date('n', mktime(0,0,0,($myMonth+1),28,$myYear));         // NEXT month of year (1-12)
$d_monthname_next = date('F', mktime(0,0,0,($myMonth+1),28,$myYear));         // NEXT Month Long name (July)
$d_year_previous = date('Y', mktime(0,0,0,$myMonth,28,($myYear-1)));        // PREVIOUS year
$d_year_next = date('Y', mktime(0,0,0,$myMonth,28,($myYear+1)));        // NEXT year

$d_weeksleft = (52 - $d_weekofyear);                     // how many weeks left in year
$d_daysinyear = $d_isleapyear ? 366 : 365;                // set correct days in year for leap years
$d_daysleft = ($d_daysinyear - $d_dayofyear);                // how many days left in year
?>

down

-4

info at djdb dot be ¶

10 years ago


raw date to clean timestamp
 private function dateToTimestamp($date){
        $datefrom = explode(" ", $date);
        $value = array();
        if(strpos($datefrom[0], '-')){
            //print "issplit -";
            $value = explode("-", $datefrom[0]);
        }
        if(strpos($datefrom[0], '/')){
            //print "issplit /";
            $value = explode("/", $datefrom[0]);
        }
        /*if(){
            
        }*/
        if(strlen($value[2])==4){//13/12/2012
            //int mktime([hour[minute[second[month[day[year
            return mktime(0, 0, 0,$value[1],$value[0],$value[2]);
        }else{                  //2012/12/13
            //int mktime([hour[minute[second[month[day[year
            return mktime(0, 0, 0,$value[1],$value[2],$value[0]);
        }
    }

down

-1

utilmind ¶

7 years ago


// here is the function which returns the Unix timestamp of last date of quarter, by  quarter number:
function last_day_of_quarter($q) {
  return mktime(0, 0, 0, floor($q*3), $q == 1 || $q == 4 ? 31 : 30);
}

down

-2

mktime_php at mailinator dot com ¶

8 years ago


One practical and useful example of using negative values in mktime is the following:

<?php
//Considering today's date
echo date('Y-m-d'); //Prints: 2016-03-22
echo date('Y-m-d', mktime(0, 0, 0, date("m"), date("d")-42, date("Y"))); //Prints: 2016-02-09
?>

By using date outputs inside mktime and adding or subtracting from them may be simpler than using other methods (string concatenations or timestamp values) and less prone to human calculations' errors.

down

-6

Stephen ¶

17 years ago


There are several warnings here about using mktime() to determine a date difference because of daylight savings time. However, nobody seems to have mentioned the other obvious problem, which is leap years.



Leap years mean that any effort to use mktime() and time() to determine the age (positive or negative) of some timestamp in years will be flawed. There are some years that are 366 days long, therefore you cannot say that there is a set number of seconds per year.



Timestamps are good for determining *real* time, which is not the same thing as *human calendar* time. The Gregorian calendar is only an approximation of real time, which is tweaked with daylight savings time and leap years to make it conform more to humans' expectations of how time should or ought to work. Timestamps are not tweaked and therefore are the only authoritative way of recording in computers a proper order of succession of events, but they cannot be integrated with a Gregorian system unless you take both leap years and DST into account. Otherwise, you may get the wrong number of years when you are approaching a value of exactly X years.



As for PHP, you could still use timestamps as a way of determining age if you took into account not only DST but also whether or not each year is a leap year and adjusted your calculations accordingly. However, this could become messy and inefficient. 



There is an alternative approach to calculating days given the day, month and year of the dates to be compared. Compare the years first, and then compare the month and day - if the month and day have already passed (or, if you like, if they match the current month and day), then add 1 to the total for the years. 



This solution works because it stays within the Gregorian system and doesn't venture into the world of timestamps.



There is also the issue of leap seconds, but this will only arise if you literally need to get the *exact* age in seconds. In that case, of course, you would also need to verify that your timestamps are exactly correct and are not delayed by script processing time, plus you would need to determine whether your system conforms to UTC, etc. I expect this will hardly be an issue for anybody using PHP, however if you are interested there is an article on this issue on Wikipedia:



http://en.wikipedia.org/wiki/Leap_second

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-5

yan ¶

15 years ago


caculate days between two date

<?php
  // end date is 2008 Oct. 11 00:00:00
  $_endDate = mktime(0,0,0,11,10,2008);
  // begin date is 2007 May 31 13:26:26
  $_beginDate = mktime(13,26,26,05,31,2007);

  $timestamp_diff= $_endDate-$_beginDate +1 ;
  // how many days between those two date
  $days_diff = $timestamp_diff/86400;

?>

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-7

zfowler at unomaha dot edu ¶

14 years ago


Proper way to convert Excel dates into PHP-friendly timestamps using mktime():



<?php

// The date 6/30/2009 is stored as 39994 in Excel

$days = 39994;



// But you must subtract 1 to get the correct timestamp

$ts = mktime(0,0,0,1,$days-1,1900);



// So, this would then match Excel's representation:

echo date("m/d/Y",$ts);

?>



Excel uses "number of days since Jan. 1, 1900" to store its dates.  It also treats 1900 as a leap year when it wasn't, thus there is an extra day which must be accounted for in PHP (and the rest of the world).  Subtracting 1 from Excel's number will fix this problem.

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-5

ooogla at hotmail dot com ¶

15 years ago


If you want to increment the day based on a variable when using a loop you can use this when you submit a form

1. Establish a start date and end date in two different variables

2. Get the number of days between a date

$ndays = (strtotime($_POST['edate']) - strtotime($_POST['sdate'])) / (60 * 60 * 24);

Then here is the string you slip in your loop

$nextday  = date('Y-m-d', mktime(0, 0, 0, date("m", strtotime($_POST['sdate']))  , date("d", strtotime($_POST['sdate']))+ $count, date("Y", strtotime($_POST['sdate']))));

$count is incremented by the loop.

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-3

A.Ross ¶

7 years ago


What's odd is that mktime doesn't seem to support every possible year number. It's common sense that 2 digit (shortened) year numbers are interpreted in the range 1970..2069

However, when padded with zeroes, no such transformation should happen (at least that is the behaviour of other date functions). Unfortunately it does (until year 100 *inclusive*):

<?php
echo date("Y-m-d",mktime(0,0,0,1,1,"0001"));
// Expected: 0001-01-01
// Result:   2001-01-01      INCORRECT

echo date("Y-m-d",mktime(0,0,0,1,1,"0100"));
// Expected: 0100-01-01
// Result:   2000-01-01      INCORRECT

echo date("Y-m-d",mktime(0,0,0,1,1,"0101"));
// Expected: 0101-01-01
// Result:   0101-01-01      Correct
?>

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-10

cebleo at n-trance dot net ¶

14 years ago


to ADD or SUBSTRACT times NOTE that if you dont specify the UTC zone your result is the difference +- your server UTC delay.



if you are ina utc/GMT +1



<?php

$hours_diff = strtotime("20:00:00")-strtotime("19:00:00");

echo  date('h:i', $hours_diff)." Hours";

?>



it shows: 02:00 Hours



but if you use a default UTC time:



<?php

date_default_timezone_set('UTC');

$hours_diff = strtotime("20:00:00")-strtotime("19:00:00");

echo "<br>". date('h:i', $hours_diff);

?>



it shows: 01:00 Hours.

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-7

Jacob Santos ¶

11 years ago


Please note that incrementing a date using mktime in a loop is not proper. You could do it, except that there is a far better method found in the DateTime PHP class. Look at the documentation for DateTime::modify, DateTime::add (when supported) and DateTime::sub (when supported).

Also, adding seconds to a time is, well it isn't as easy as it seems, "Hey I'll just add 3600 seconds or 86400 seconds or x seconds!". The phrase once bitten, twice shy is quite applicable with the usage of adding seconds. If you ever had to 'fix' a time by calculating midnight to add the correct number of seconds, then you are doing it wrong. 

Luckily, knowing is not a requirement, because DateTime and friends exists, removing the complexity for you.

So if given a choice of

mktime($seconds, $minutes, $hours+1);

and

$datetime->modify('+1 hour');

or

$datetime->add('P1H');

I'll go with the second choice, but probably not the third, unless I was using DateInterval::createFromDateString, so that other developers knew my intent.

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-8

rlz ¶

16 years ago


Finding out the number of days in a given month and year, accounting for leap years when February has more than 28 days.



<?php

function days_in_month($year, $month) {

    return( date( "t", mktime( 0, 0, 0, $month, 1, $year) ) );

}

?>



Hope it helps a soul out there.

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-10

ionut dot bodea at eydos dot ro ¶

15 years ago


Here is what I use to calculate age. It took me 30 minutes to write and it's quite accurate. What it has special is that it's calculating the number of days a year has (float number), by testing if a year is a leap one or not. This number is used to compute the age.



<?php

function get_age($date_start, $date_end) {

    $t_lived = get_timestamp($date_end) - get_timestamp($date_start);

    $seconds_one_year = get_days_per_year($date_start, $date_end) * 24 * 60 * 60;

    $age = array();

    $age['years_exact'] = $t_lived / $seconds_one_year;

    $age['years'] = floor($t_lived / $seconds_one_year);

    $seconds_remaining = $t_lived % $seconds_one_year;

    $age['days'] = round($seconds_remaining / (24 * 60 * 60));

    return $age;

}

function get_timestamp($date) {

    list($y, $m, $d) = explode('-', $date);

    return mktime(0, 0, 0, $m, $d, $y);

}

function get_days_per_year($date_start, $date_end) {

    list($y1) = explode('-', $date_start);

    list($y2) = explode('-', $date_end);

    $years_days = array();

    for($y = $y1; $y <= $y2; $y++) {

        $years_days[] = date('L', mktime(0, 0, 0, 1, 1, $y)) ? 366 : 365;

    }

    return round(array_sum($years_days) / count($years_days), 2);

}



$date_birth = '1979-10-12';

$date_now = date('Y-m-d');



$age = get_age($date_birth, $date_now);

echo '<pre>';

print_r($age);

echo '</pre>';

?>





It will display something like this:

Array

(

    [years_exact] => 28.972974329491

    [years] => 28

    [days] => 355

)

down

-11

mogster at redesign dot no ¶

10 years ago


Just a simple function to return mktime from a db (mysql) datetime (Y-m-d H:i:s):

function retMktimest($dbdate) {
  return mktime(substr($dbdate, 11, 2), substr($dbdate, 14, 2), substr($dbdate, 17, 2), substr($dbdate, 5, 2), substr($dbdate, 8, 2), substr($dbdate, 0, 4));
}

down

-12

delfino dot salinas at gmail dot com ¶

10 years ago


this function returns the number of days of a provided month and year, it consider the actual rules for leap years 

(if the year is multiple of 4 which is not a multiple of 100 unless multiple of thousand then is a leap)
Regards, hope this function solves any issue :)

function daysinmonth($month,$year) {
$dim = 0;
switch ($month) {
    case 1:
    case 3:
    case 5:
    case 7:
    case 8:
    case 10:
    case 12:
        $dim=31;
        break;
    case 4:
    case 6:
    case 9:
    case 11:
        $dim=30;
        break;
    case 2:
        if($year%4==0) {
            if($year%100==0) {
                if($year%1000==0) { $dim=29; } else { $dim=28; }
            } else {
                $dim=29;
            }
        } else {$dim=28;}
        break;
    }
    return($dim); 
}

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