IntlDateFormatter::parse

datefmt_parse

(PHP 5 >= 5.3.0, PHP 7, PHP 8, PECL intl >= 1.0.0)

IntlDateFormatter::parse -- datefmt_parseParse string to a timestamp value

Описание

Объектно-ориентированный стиль

public IntlDateFormatter::parse(string $string, int &$offset = null): int|float|false

Процедурный стиль

datefmt_parse(IntlDateFormatter $formatter, string $string, int &$offset = null): int|float|false

Converts string to an incremental time value, starting at offset and consuming as much of the input value as possible.

Список параметров

formatter

The formatter resource

string

string to convert to a time

offset

Position at which to start the parsing in string (zero-based). If no error occurs before string is consumed, offset will contain -1 otherwise it will contain the position at which parsing ended (and the error occurred). This variable will contain the end position if the parse fails. If offset > strlen($string), the parse fails immediately.

Возвращаемые значения

Timestamp of parsed value, or false if value cannot be parsed.

Примеры

Пример #1 OO example

<?php
$fmt 
= new IntlDateFormatter(
    
'en_US',
    
IntlDateFormatter::FULL,
    
IntlDateFormatter::FULL,
    
'America/Los_Angeles',
    
IntlDateFormatter::GREGORIAN
);
echo 
'First parsed output is ' $fmt->parse('Wednesday, December 20, 1989 4:00:00 PM PT');
$fmt = new IntlDateFormatter(
    
'de-DE',
    
IntlDateFormatter::FULL,
    
IntlDateFormatter::FULL,
    
'America/Los_Angeles',
    
IntlDateFormatter::GREGORIAN
);
?>

Пример #2 datefmt_parse() example

<?php
$fmt 
datefmt_create(
    
'en_US',
    
IntlDateFormatter::FULL,
    
IntlDateFormatter::FULL,
    
'America/Los_Angeles',
    
IntlDateFormatter::GREGORIAN
);
echo 
'First parsed output is ' datefmt_parse($fmt'Wednesday, December 20, 1989 4:00:00 PM PT');
$fmt datefmt_create(
    
'de-DE',
    
IntlDateFormatter::FULL,
    
IntlDateFormatter::FULL,
    
'America/Los_Angeles',
    
IntlDateFormatter::GREGORIAN
);
echo 
'Second parsed output is ' datefmt_parse($fmt'Mittwoch, 20. Dezember 1989 16:00 Uhr GMT-08:00');
?

Результат выполнения данного примера:

First parsed output is 630201600
Second parsed output is 630201600

Смотрите также

add a note add a note

User Contributed Notes 1 note

up
0
Anonymous
5 years ago
Please note:
* on  a 32-bit system, parse() will return float if the value gets out of integer range
* while parse() parses fractional seconds with a format like 'yyyy-MM-dd HH:mm:ss.SSSSSS', it only returns an int. This is also true when the value is returned as float, msecs remain absent in the return value.
To Top