As far as I remember interface_exists() was added in 5.0.2 . In 5.0.0 and 5.0.1 class_exists() used to return TRUE when asked for a existing interface. Starting 5.0.2 class_exists() doesn't do that anymore.
interface_exists
(PHP 5 >= 5.0.2, PHP 7, PHP 8)
interface_exists — Checa se a interface foi definida
Descrição
interface_exists
( string
$interface_name
, bool $autoload = ?
) : boolVerifica se uma interface foi definida.
Valor Retornado
Essa função retorna true se a interface de nome
interface_name já foi definida, false caso contrário.
Exemplos
Exemplo #1 Exemplo de uso de interface_exists()
<?php
// Check the interface exists before trying to use it
if (interface_exists('MyInterface')) {
class MyClass implements MyInterface
{
// Methods
}
}
?>
add a note
User Contributed Notes 4 notes
andrey at php dot net ¶
19 years ago
CoR ¶
8 years ago
Class and Interface share SAME namespace!
class k{}
interface k {} // Fatal error: Cannot redeclare class k
maxim at inbox dot ru ¶
11 years ago
If you want to check for included interface and you already register spl autoloader - it will crash. Becassue autoloader trying to load `string` and he doesnt matter is it class or not.
Iv found several ways :
1 - unregister AL - -> check for Ifaces - -> register Autoloader
2 - $ifaces = array_flip(get_declared_interfaces());
if($ifaces["MyIface"]) // empty // isset .
Interfaces are not bad, you can build correct geomentry of system , with validation by funcs / vars / const .
Also they are good to storage variables <?php
ROOT::THEMES ; ROOT::LOC ; ?> . Much faster then Define, but you cant put algorithms inside, only complite strings / __file__ / etc.
nils dot rocine at gmail dot com ¶
12 years ago
A little note on namespaces that may be obvious to some, but was not obvious to me.
Although you can make the below statement when the statement is in the same namespace as the interface/class declaration MyInterface...
<?php
$foo instanceof MyInterface
?>
Making use of the interface_exists, or class_exists functions, you must enter the full namespaced interface name like so (even if the function call is from the same namespace.)
<?php
interface_exists(__NAMESPACE__ . '\MyInterface', false);
?>
